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-3y^2+15y-18=0
a = -3; b = 15; c = -18;
Δ = b2-4ac
Δ = 152-4·(-3)·(-18)
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-3}{2*-3}=\frac{-18}{-6} =+3 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+3}{2*-3}=\frac{-12}{-6} =+2 $
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